Contest link : Intra AUST Preliminary Spring - 17
Diamond lover : Just implement the diamond shape and carefully calculate the spaces between the diamonds.
Easy to solve 1 : From 0 to N, if we X-OR all the integers, we get a binary representation which length is exactly the same length as N. As N is large, using brute force to generate result won't help. We just need to find the binary representation of N and replace every digit with "1". The decimal format of that is the answer.
Strength check : Just check all the information about the password is whether present in the string or not.
Can you solve it? : It's a bit manipulation problem. If you are familiar with the concept of bit handling it should be easy for you. However, I found a pattern and solved it accordingly. Here is how : Can you solve it?
Longest String : A simple brute force will be enough for the solution. Just implement the code and keep in mind about the alphabetical order.
Diamond lover : Just implement the diamond shape and carefully calculate the spaces between the diamonds.
Easy to solve 1 : From 0 to N, if we X-OR all the integers, we get a binary representation which length is exactly the same length as N. As N is large, using brute force to generate result won't help. We just need to find the binary representation of N and replace every digit with "1". The decimal format of that is the answer.
Strength check : Just check all the information about the password is whether present in the string or not.
Can you solve it? : It's a bit manipulation problem. If you are familiar with the concept of bit handling it should be easy for you. However, I found a pattern and solved it accordingly. Here is how : Can you solve it?
Longest String : A simple brute force will be enough for the solution. Just implement the code and keep in mind about the alphabetical order.
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